Kranga•2y ago

Is it possible to call a query from another query defined in the same router?

Say I have some code like the following:

t.router({
    compute_all: t.procedure
        .query(async ({ctx, input})=>{
            //Receives an array of computable objects and applies the transformation defined in compute_one
            const result = await Promise.all(input.datasets.map(x=>/*SOMETHING_SHOULD_BE_HERE*/));
            return result;
        }),
    compute_one: t.procedure
        .query(async ({ctx, input})=>{
            const result = '...';//Fetches data and does some transformation on it
            return result;
        })
})

t.router({
    compute_all: t.procedure
        .query(async ({ctx, input})=>{
            //Receives an array of computable objects and applies the transformation defined in compute_one
            const result = await Promise.all(input.datasets.map(x=>/*SOMETHING_SHOULD_BE_HERE*/));
            return result;
        }),
    compute_one: t.procedure
        .query(async ({ctx, input})=>{
            const result = '...';//Fetches data and does some transformation on it
            return result;
        })
})

Is it posible to reuse the compute_one query logic within the compute_all query without extracting the common logic outside the router? I have tried doing it via instantiating a client using that same router and executing the query as usual from within the query but I get

'default' implicitly has type 'any' because it does not have a type annotation and is referenced directly or indirectly in its own initializer.

due to the router=>client=>router circular reference.

2 Replies

Unknown User•2y ago

Message Not Public

KrangaOP•2y ago

I get the same error due to circular references router=>caller=>router