Use zod with custom interface type?

Original message was deleted

Mapo Doofus•4/2/23, 7:14 PM

This is more of a zod question than a trpc question. Zod is a runtime validator so you need to create the validator and then get the type from that. See the example from zod docs below.

// all properties are required by default
const Dog = z.object({
  name: z.string(),
  age: z.number(),
});

// extract the inferred type like this
type Dog = z.infer<typeof Dog>;

// equivalent to:
type Dog = {
  name: string;
  age: number;
};

// all properties are required by default
const Dog = z.object({
  name: z.string(),
  age: z.number(),
});

// extract the inferred type like this
type Dog = z.infer<typeof Dog>;

// equivalent to:
type Dog = {
  name: string;
  age: number;
};

Nick•4/2/23, 10:25 PM

You could probably also check your output works with something like zodInvoice satisfies ZodType<Invoice, any, any>zodInvoice satisfies ZodType<Invoice, any, any>

Might take some tweaks from that ideation though