Typescript helper for router output

is there a helper to do this better? Get the output for a certain route? Or is this the way to do it?

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff

Solution

is there a helper to do this better? Get the output for a certain route? Or is this the way to do it?

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff

tRPC•3y ago•

4 replies

is there a helper to do this better? Get the output for a certain route? Or is this the way to do it?

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff

Solution

is there a helper to do this better? Get the output for a certain route? Or is this the way to do it?

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff

import type { AppRouter } from "$lib/api/root";

type TInitialData = AppRouter['user']['me']['_def']['_output_out']

// Do stuff