How to Type a Middleware factory?

Lemme first show you what I want, so you can get the gist of it. (Consider me less experienced in typescript)

publicProcedure
    .input(z.object({ test: z.boolean() }))
    .use(middlewareFactory( /** TO GET INPUT TYPECHECKING HERE */ ))

publicProcedure
    .input(z.object({ test: z.boolean() }))
    .use(middlewareFactory( /** TO GET INPUT TYPECHECKING HERE */ ))

This is what I put together. This almost works

/// types
type CustomPParams<T> = ProcedureParams<AnyRootConfig,unknown,unknown,T,unknown,unknown,unknown>
type MiddlewareFactory = <T>(input: T) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

/// a middleware factory
export const middlewareFactory: MiddlewareFactory = input => ({ next }) => { return next() }

/// types
type CustomPParams<T> = ProcedureParams<AnyRootConfig,unknown,unknown,T,unknown,unknown,unknown>
type MiddlewareFactory = <T>(input: T) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

/// a middleware factory
export const middlewareFactory: MiddlewareFactory = input => ({ next }) => { return next() }

I get autocompletion in vscode, but when I press tab and proceed with the autocompletion, I get an error that looks like this (the screenshot attached). Feels like i'm in the right path but cant exactly make a solid type out it.

Now, for my very specific use case, i did make an workaround by making that

generic partial

type MiddlewareFactory = <T>(input: Partial<T>) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

type MiddlewareFactory = <T>(input: Partial<T>) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

But this feels like a half measure. And provided that different validation libs might affect the type of input in subtle ways, I need to know how to properly type this thing.

Thank you

How to Type a Middleware factory?

Lemme first show you what I want, so you can get the gist of it. (Consider me less experienced in typescript)

publicProcedure
    .input(z.object({ test: z.boolean() }))
    .use(middlewareFactory( /** TO GET INPUT TYPECHECKING HERE */ ))

publicProcedure
    .input(z.object({ test: z.boolean() }))
    .use(middlewareFactory( /** TO GET INPUT TYPECHECKING HERE */ ))

This is what I put together. This almost works

/// types
type CustomPParams<T> = ProcedureParams<AnyRootConfig,unknown,unknown,T,unknown,unknown,unknown>
type MiddlewareFactory = <T>(input: T) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

/// a middleware factory
export const middlewareFactory: MiddlewareFactory = input => ({ next }) => { return next() }

/// types
type CustomPParams<T> = ProcedureParams<AnyRootConfig,unknown,unknown,T,unknown,unknown,unknown>
type MiddlewareFactory = <T>(input: T) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

/// a middleware factory
export const middlewareFactory: MiddlewareFactory = input => ({ next }) => { return next() }

generic partial

type MiddlewareFactory = <T>(input: Partial<T>) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

type MiddlewareFactory = <T>(input: Partial<T>) => MiddlewareFunction<CustomPParams<T>, ProcedureParams>

But this feels like a half measure. And provided that different validation libs might affect the type of input in subtle ways, I need to know how to properly type this thing.

Thank you

How to Type a Middleware factory?

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