DangerZone•5mo ago

Validating inputs and outputs only via typescript

Hey everyone, I am trying to create an appRouter with ts-morph but I am having trouble with passing the zod schema/object instance to it (since I need to pass the original implementation, not the instance). I was thinking about a way to work around this and was wondering if I could somehow just pass the zod typescript type in the inputs and outputs - keep in mind that my usecase only calls for the type definitions to work, not the actual implementation.

import { initTRPC } from '@trpc/server';
import { z } from 'zod';

const t = initTRPC.create();
const publicProcedure = t.procedure;

const randomSchema = z.object({
  name: z.string(),
});

type RandomType = z.infer<typeof randomSchema>;

const appRouter = t.router({
  UserRouter: {
    hello: publicProcedure.input<RandomType>().query((opts) => {
      const name = opts.input.name;
      return {
        greeting: `Hello ${opts.input.name}`,
      };
    }),
  },
});
export type AppRouter = typeof appRouter;

import { initTRPC } from '@trpc/server';
import { z } from 'zod';

const t = initTRPC.create();
const publicProcedure = t.procedure;

const randomSchema = z.object({
  name: z.string(),
});

type RandomType = z.infer<typeof randomSchema>;

const appRouter = t.router({
  UserRouter: {
    hello: publicProcedure.input<RandomType>().query((opts) => {
      const name = opts.input.name;
      return {
        greeting: `Hello ${opts.input.name}`,
      };
    }),
  },
});
export type AppRouter = typeof appRouter;

here you can see I am trying to pass on;y the RandomType, but ofc I don't really know what I am doing 😄

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