sanitizing output based on output schema

As i understand, the

.output

.output

will only ensure the schema is respected, but will not sanitize output on the go (even tho it could be possible with a

z.strictObject()

z.strictObject()

.output(someSchema) // <- does not sanitize data
// ---
.use(output(someSchema)) // <- should sanatize data

export function output<T extends ZodType>(schema: T) {
  return middleware(async ({ next }) => {
    const result = await next()
    return schema.parse(result)
  })
}

.output(someSchema) // <- does not sanitize data
// ---
.use(output(someSchema)) // <- should sanatize data

export function output<T extends ZodType>(schema: T) {
  return middleware(async ({ next }) => {
    const result = await next()
    return schema.parse(result)
  })
}

but for some reason the typing does not work. could somebody point out how to achieve similar but in a working way? is there no way to do what i want?

tRPC•8mo ago•

1 reply

y_nk

sanitizing output based on output schema

As i understand, the

.output

.output

will only ensure the schema is respected, but will not sanitize output on the go (even tho it could be possible with a

z.strictObject()

z.strictObject()

.output(someSchema) // <- does not sanitize data
// ---
.use(output(someSchema)) // <- should sanatize data

export function output<T extends ZodType>(schema: T) {
  return middleware(async ({ next }) => {
    const result = await next()
    return schema.parse(result)
  })
}

.output(someSchema) // <- does not sanitize data
// ---
.use(output(someSchema)) // <- should sanatize data

export function output<T extends ZodType>(schema: T) {
  return middleware(async ({ next }) => {
    const result = await next()
    return schema.parse(result)
  })
}

but for some reason the typing does not work. could somebody point out how to achieve similar but in a working way? is there no way to do what i want?

sanitizing output based on output schema

sanitizing output based on output schema

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